Friday 11 July 2014

Character is present or not in a string using OOP



#include<conio.h>
#include<iostream.h>
#include<string.h>
#include<stdio.h>
class character
{
char a,str[50];
int i,flag;
public:
void readdata();
void result();
};

void character::readdata()
{
cout<<"Enter a string:";
gets(str);
cout<<"Enter a charecter:";
cin>>a;
flag=0;
for(i=0;str[i]!='\0';i++)

if(str[i]==a)

flag=1;
}
void character::result()
{
if (flag==1)
cout<<"charecter is present";
else
cout<<"charecter is not present:";
}
void main()
{
clrscr();
character obj;
obj.readdata();
obj.result();
getch();
}

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